In a dihybrid cross, the maximum number of phenotypes would be

Question

In a dihybrid cross, the maximum number of phenotypes would be (A) 8 (B) 4 (C) 2 (D) 16

Tardigrade Admin · Accepted Answer

Monohybrid cross produces 2 phenotypes Dihybrid cross productes 4 phenotypes Trihybrid cross produces 8 phenotypes Total number of phenotypes = 2n Total number of genotypes = 3n Where n = type of cross (for monohybrid n = 1, for dihybrid n = 2 and....so, on)

Q. In a dihybrid cross, the maximum number of phenotypes would be

$8$

$4$

$2$

$16$

Monohybrid cross produces $2$ phenotypes
Dihybrid cross productes $4$ phenotypes
Trihybrid cross produces $8$ phenotypes
Total number of phenotypes $= 2^{n}$
Total number of genotypes $= 3^{n}$
Where $n =$ type of cross (for monohybrid $n = 1$ , for dihybrid $n = 2$ and....so, on)

Q. In a dihybrid cross, the maximum number of phenotypes would be

8

4

2

16

Monohybrid cross produces 2 phenotypes Dihybrid cross productes 4 phenotypes Trihybrid cross produces 8 phenotypes Total number of phenotypes =2n Total number of genotypes =3n Where n= type of cross (for monohybrid n=1, for dihybrid n=2 and....so, on)

$8$

$4$

$2$

$16$

Monohybrid cross produces $2$ phenotypes
Dihybrid cross productes $4$ phenotypes
Trihybrid cross produces $8$ phenotypes
Total number of phenotypes $= 2^{n}$
Total number of genotypes $= 3^{n}$
Where $n =$ type of cross (for monohybrid $n = 1$ , for dihybrid $n = 2$ and....so, on)