In a compound A containing carbon, hydrogen and oxygen, the % of hydrogen is one sixth that of carbon which is 1.5 times that of oxygen. What is the simplest formula for the compound :

Question

In a compound A containing carbon, hydrogen and oxygen, the % of hydrogen is one sixth that of carbon which is 1.5 times that of oxygen. What is the simplest formula for the compound : (A) C2H4O2 (B) C2H4O (C) C2H6O (D) CH4O

Tardigrade Admin · Accepted Answer

Let % of oxygen =x % of H =(1/6) × % of C =(1.5 x /6) % C =1.5 × % of O =1.5 × x element % A %/A Simple ratio C 1.5 x 12 (1.5 x/12) (1.5 x/6) × 16 = 2 H (1.5x/6) 1 (1.5 x/6) (1.5 x/6) × 16 = 2 O x 16 (x/16) =1 Empirical formula =C2H4O

element	%	A	%/A	Simple ratio
C	1.5 x	12	$\frac{1.5 x}{12}$	$\frac{1.5 x}{6} \times 16 = 2$
H	$\frac{1.5 x}{6}$	1	$\frac{1.5 x}{6}$	$\frac{1.5 x}{6} \times 16 = 2$
O	x	16	$\frac{x}{16}$	$= 1$

Q. In a compound $A$ containing carbon, hydrogen and oxygen, the $%$ of hydrogen is one sixth that of carbon which is $1.5$ times that of oxygen. What is the simplest formula for the compound :

$C_{2} H_{4} O_{2}$

$C_{2} H_{4} O$

$C_{2} H_{6} O$

$C H_{4} O$

Q. In a compound A containing carbon, hydrogen and oxygen, the % of hydrogen is one sixth that of carbon which is 1.5 times that of oxygen. What is the simplest formula for the compound :

C2​H4​O2​

C2​H4​O

C2​H6​O

CH4​O

Let % of oxygen =x % of H=61​×% of C=61.5x​ %C=1.5×% of O=1.5×x element % A %/A Simple ratio C 1.5 x 12 121.5x​ 61.5x​×16=2 H 61.5x​ 1 61.5x​ 61.5x​×16=2 O x 16 16x​ =1 Empirical formula =C2​H4​O

Q. In a compound $A$ containing carbon, hydrogen and oxygen, the $%$ of hydrogen is one sixth that of carbon which is $1.5$ times that of oxygen. What is the simplest formula for the compound :

$C_{2} H_{4} O_{2}$

$C_{2} H_{4} O$

$C_{2} H_{6} O$

$C H_{4} O$