In a certain operation 358 g of TiCl4 is reacted with 96 g of Mg. Calculate % yield of Ti if 32 g of Ti is actually obtained [At. wt. Ti = 48, Mg = 24][ Hint: (358/190) = 1.88]

Question

In a certain operation 358 g of TiCl4 is reacted with 96 g of Mg. Calculate % yield of Ti if 32 g of Ti is actually obtained [At. wt. Ti = 48, Mg = 24][ Hint: (358/190) = 1.88] (A) 35.38 % (B) 66.6 % (C) 100 % (D) 60 %

Tardigrade Admin · Accepted Answer

TiCl4 + 2Mg → Ti + 2MgCl2 Initial mole (358/190) = 1.88 (96/24) = 4 final mole 0 4-2 × 1.88 1.88 2× 1.88 Weight of Ti obtained = (358/190) × 48 % Yield = ((32× 100/358 × 48)/190) = 35.38 %

Q. In a certain operation $358 g$ of $T i C l_{4}$ is reacted with $96$ g of $M g$ . Calculate $%$ yield of $T i$ if $32 g$ of $T i$ is actually obtained [At. wt. $T i = 48, M g = 24] [$ Hint: $\frac{358}{190} = 1.88]$

$35.38%$

$66.6%$

$100%$

$60%$

$T i C l_{4} + 2 M g \to T i + 2 M g C l_{2}$
Initial mole $\frac{358}{190} = 1.88 \frac{96}{24} = 4$
final mole $04 - 2 \times 1.88 1.88 2 \times 1.88$
Weight of $T i$ obtained $= \frac{358}{190} \times 48$
$%$ Yield $= \frac{\frac{32 \times 100}{358 \times 48}}{190} = 35.38%$

Q. In a certain operation 358g of TiCl4​ is reacted with 96 g of Mg. Calculate % yield of Ti if 32g of Ti is actually obtained [At. wt. Ti=48,Mg=24][ Hint: 190358​=1.88]

35.38%

66.6%

100%

60%