Q.
In a car lift, compressed air exerts a force F, on a small piston having a radius of 5.0cm. This pressure is transmitted to a second piston of radius 15cm. If the mass of the car to be lifted is 1350kg, calculate F.
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Mechanical Properties of Solids
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Solution:
Since pressure is transmitted undiminished throughout the fluid, F1=A1(A2F2) =π(15×10−2m)2π(5×10−2m)2×(1350kg×9.8ms−2) =1470N=15×103N