Q.
In a calorimeter of water equivalent 20g, water of mass 1.1kg is taken at 288K temperature. If steam at temperature 373K is passed through it and temperature of water increases by 6.5∘C then the mass of steam condensed is
Let mass of steam that gets condenced while the temperature of water is raised by 6.5∘C=xg
So, heat released by steam =540xcal+x×1×78.5 [Q=mL+msΔT]
This heat goes to the water + calorimeter system Q required by water =1100×1×6.5=7150cal Q required by calorimeter =20×1×6.5=130cal Qreleased =Qrequired 78.5x+540x=7150+130 x≃11.7g