In a batch of 15 students, if the marks of 10 students who passed are 70, 50, 95, 40, 60, 70, 80, 90, 75, 80 then the median marks of all the 15 students is:

Question

In a batch of 15 students, if the marks of 10 students who passed are 70, 50, 95, 40, 60, 70, 80, 90, 75, 80 then the median marks of all the 15 students is: (A) 40 (B) 50 (C) 60 (D) 70

Tardigrade Admin · Accepted Answer

As given: marks of 10 students out of 15 in the ascending order are 40, 50, 60, 70, 70, 75, 80, 80, 90, 95 Total number of terms = 15 and 5 students who failed are below 40 marks, median = ( (n + 1/2) ) th term = ( (15 + 1/2) )th term = 8th term = 60

Q. In a batch of 15 students, if the marks of 10 students who passed are 70, 50, 95, 40, 60, 70, 80, 90, 75, 80 then the median marks of all the 15 students is:

40

50

60

70

As given : marks of 10 students out of 15 in the ascending order are 40, 50, 60, 70, 70, 75, 80, 80, 90, 95
Total number of terms = 15 and 5 students
who failed are below 40 marks, median = $(\frac{n + 1}{2}) t h$ term
$= (\frac{15 + 1}{2})^{t h}$ term $= 8^{t h}$ term = 60

Q. In a batch of 15 students, if the marks of 10 students who passed are 70, 50, 95, 40, 60, 70, 80, 90, 75, 80 then the median marks of all the 15 students is:

40

50

60

70

As given : marks of 10 students out of 15 in the ascending order are 40, 50, 60, 70, 70, 75, 80, 80, 90, 95 Total number of terms = 15 and 5 students who failed are below 40 marks, median = (2n+1​)th term =(215+1​)th term =8th term = 60

As given : marks of 10 students out of 15 in the ascending order are 40, 50, 60, 70, 70, 75, 80, 80, 90, 95
Total number of terms = 15 and 5 students
who failed are below 40 marks, median = $(\frac{n + 1}{2}) t h$ term
$= (\frac{15 + 1}{2})^{t h}$ term $= 8^{t h}$ term = 60