In 1 m long open pipe, what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz

Question

In 1 m long open pipe, what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz (A) First (B) Second (C) Third (D) Fourth

Tardigrade Admin · Accepted Answer

For an open organ pipe n=n prime (v/2 l) n=480 Hz , ℓ=1 m , v =330 m / s n prime=( n (2 ℓ)/ v ) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a6b16ab8b272d67b1f4c847859d14eeb-.png" /> =(480 × 2 × 1/330) =(32/11) ≈ 3

Q. In 1 m long open pipe, what is the harmonic of resonance obtained with a tuning fork of frequency $480 Hz$

First

Second

Third

Fourth

For an open organ pipe
$n = n^{'} \frac{v}{2 l}$
$n = 480 Hz, ℓ = 1 m, v = 330 m / s$
$n^{'} = \frac{n ( 2 ℓ )}{v}$

$= \frac{480 \times 2 \times 1}{330}$
$= \frac{32}{11} \approx 3$

Q. In 1 m long open pipe, what is the harmonic of resonance obtained with a tuning fork of frequency 480Hz