Q.
If ∣z1∣=∣z2∣=∣z3∣=1 and z1,z2,z3 are represented by the vertices of an equilateral triangle then which of the following is not true?
157
160
Complex Numbers and Quadratic Equations
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Solution:
All the three vertices lies on circle ∣z∣=1.
Take z1=z1,z2=z1ω,z3=z1ω2
So z1+z2+z3=z1(1+ω+ω2)=0 z1z2z3=z13 z1z2+z2z3+z3z1=z12(ω+ω3+ω2)=0