If xgm of steam at 100° C becomes water at 100° C which converts y gm of ice at 0° C into water at 100° C , then the ratio (x/y) will be,

Question

If xgm of steam at 100° C becomes water at 100° C which converts y gm of ice at 0° C into water at 100° C , then the ratio (x/y) will be, (A) (1/3) (B) (27/4) (C) 3 (D) (4/27)

Tardigrade Admin · Accepted Answer

Heat loss by steam will be equal to heat gained by water at 100° C . Therefore, x× 540=(y × 80)+(y × 1 × 100) , ⇒ 540x=180y ⇒ (x/y)=(1/3)

Q. If $xg m$ of steam at $10 0^{\circ} C$ becomes water at $10 0^{\circ} C$ which converts $y g m$ of ice at $0^{\circ} C$ into water at $10 0^{\circ} C$ , then the ratio $\frac{x}{y}$ will be,

$\frac{1}{3}$

$\frac{27}{4}$

$3$

$\frac{4}{27}$

Heat loss by steam will be equal to heat gained by water at $10 0^{\circ} C$ .
Therefore,
$x \times 540 = (y \times 80) + (y \times 1 \times 100)$ ,
$\Rightarrow 540 x = 180 y$
$\Rightarrow \frac{x}{y} = \frac{1}{3}$

Q. If xgm of steam at 100∘C becomes water at 100∘C which converts ygm of ice at 0∘C into water at 100∘C , then the ratio yx​ will be,

31​

427​

3

274​

Heat loss by steam will be equal to heat gained by water at 100∘C . Therefore, x×540=(y×80)+(y×1×100) , ⇒540x=180y ⇒yx​=31​

Q. If $xg m$ of steam at $10 0^{\circ} C$ becomes water at $10 0^{\circ} C$ which converts $y g m$ of ice at $0^{\circ} C$ into water at $10 0^{\circ} C$ , then the ratio $\frac{x}{y}$ will be,

$\frac{1}{3}$

$\frac{27}{4}$

$3$

$\frac{4}{27}$

Heat loss by steam will be equal to heat gained by water at $10 0^{\circ} C$ .
Therefore,
$x \times 540 = (y \times 80) + (y \times 1 \times 100)$ ,
$\Rightarrow 540 x = 180 y$
$\Rightarrow \frac{x}{y} = \frac{1}{3}$