If (x, y) is a variable point on the line y=2 x lying between the lines 2(x+1)+y=0 and x+3(y-1)=0, then

Question

If (x, y) is a variable point on the line y=2 x lying between the lines 2(x+1)+y=0 and x+3(y-1)=0, then (A) x ∈(-1 / 2,6 / 7) (B) x ∈(-1 / 2,3 / 7) (C) y ∈(-1,3 / 7) (D) y ∈(-1,6 / 7)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/6f114c81815e04f527986fe76391f780-.png" /> Solving y=2 x, 2(x+1)+y=0, we get x=-1 / 2, y=-1. Solving y=2 x, x+3(y-1)=0, we get x=3 / 7, y=6 / 7.

Q. If $(x, y)$ is a variable point on the line $y = 2 x$ lying between the lines $2 (x + 1) + y = 0$ and $x + 3 (y - 1) = 0$ , then

$x \in (- 1/2, 6/7)$

$x \in (- 1/2, 3/7)$

$y \in (- 1, 3/7)$

$y \in (- 1, 6/7)$

Solving $y = 2 x, 2 (x + 1) + y = 0$ , we get $x = - 1/2, y = - 1$ . Solving $y = 2 x, x + 3 (y - 1) = 0$ , we get $x = 3/7, y = 6/7$ .

Q. If (x,y) is a variable point on the line y=2x lying between the lines 2(x+1)+y=0 and x+3(y−1)=0, then

x∈(−1/2,6/7)

x∈(−1/2,3/7)

y∈(−1,3/7)

y∈(−1,6/7)