If x g of a metal forms y g of metal chloride, equivalent weight of metal is

Question

If x g of a metal forms y g of metal chloride, equivalent weight of metal is (A) (y - x/35.5 x) (B) (35.5 y/ y - x) (C) (35.5x/y - x) (D) (x/35.5 (y -x)

Tardigrade Admin · Accepted Answer

Wt of the metal = x g
Wt. of metal chloride = y g
Wt. of chloride = (y - x) g
(y - x) g of chloride combines with x g of metal.
35.5 g of chloride combines with

\frac{x}{( y - x )} \times 35.5

g of metal.
Hence, equivalent mass of metal =

\frac{35.5 x}{y - x}

Q. If x g of a metal forms y g of metal chloride, equivalent weight of metal is

$\frac{y - x}{35.5 x}$

$\frac{35.5 y}{y - x}$

$\frac{35.5 x}{y - x}$

$\frac{x}{35.5 (y -x) $

Wt of the metal = x g
Wt. of metal chloride = y g
Wt. of chloride = (y - x) g
(y - x) g of chloride combines with x g of metal.
35.5 g of chloride combines with $\frac{x}{( y - x )} \times 35.5$ g of metal.
Hence, equivalent mass of metal = $\frac{35.5 x}{y - x}$

Q. If x g of a metal forms y g of metal chloride, equivalent weight of metal is

35.5xy−x​

y−x35.5y​

y−x35.5x​

$\frac{x}{35.5 (y -x) $

Wt of the metal = x g Wt. of metal chloride = y g Wt. of chloride = (y - x) g (y - x) g of chloride combines with x g of metal. 35.5 g of chloride combines with (y−x)x​×35.5 g of metal. Hence, equivalent mass of metal = y−x35.5x​

$\frac{y - x}{35.5 x}$

$\frac{35.5 y}{y - x}$

$\frac{35.5 x}{y - x}$

Wt of the metal = x g
Wt. of metal chloride = y g
Wt. of chloride = (y - x) g
(y - x) g of chloride combines with x g of metal.
35.5 g of chloride combines with $\frac{x}{( y - x )} \times 35.5$ g of metal.
Hence, equivalent mass of metal = $\frac{35.5 x}{y - x}$