If x2/3-7x1/3+10=0 then, the value of x is

Question

If x2/3-7x1/3+10=0 then, the value of x is (A)  125  (B)  8  (C)  φ  (D)  text ! ! ! ! text 125,8 ! ! ! ! text

Tardigrade Admin · Accepted Answer

Given equation can be rewritten as (x1 / 3)2-7(x1 / 3)+10=0 Let α=x1 / 3 then I t reduces to α2-7 α+10=0 ⇒ (α-5)(α-2)=0 ⇒ α=5,2 ∴ α3=x ⇒ x=125 and 8 cos e c-1( sec α)+ cot -1( tan α)

Q. If $x^{2/3} - 7 x^{1/3} + 10 = 0$ then, the value of $x$ is

${125}$

${8}$

$ϕ$

${125,8}$

Given equation can be rewritten as
$(x^{1/3})^{2} - 7 (x^{1/3}) + 10 = 0$
Let $α = x^{1/3}$ then I t reduces to
$α^{2} - 7 α + 10 = 0$
$\Rightarrow (α - 5) (α - 2) = 0$
$\Rightarrow α = 5, 2$
$∴ α^{3} = x$
$\Rightarrow x = 125$ and $8$
$cos e c^{- 1} (sec α) + cot^{- 1} (tan α)$

Q. If x2/3−7x1/3+10=0 then, the value of x is

{125}

{8}

ϕ

{ 125,8 }

Given equation can be rewritten as (x1/3)2−7(x1/3)+10=0 Let α=x1/3 then I t reduces to α2−7α+10=0 ⇒(α−5)(α−2)=0 ⇒α=5,2 ∴α3=x ⇒x=125 and 8 cosec−1(secα)+cot−1(tanα)

Q. If $x^{2/3} - 7 x^{1/3} + 10 = 0$ then, the value of $x$ is

${125}$

${8}$

$ϕ$

${125,8}$

Given equation can be rewritten as
$(x^{1/3})^{2} - 7 (x^{1/3}) + 10 = 0$
Let $α = x^{1/3}$ then I t reduces to
$α^{2} - 7 α + 10 = 0$
$\Rightarrow (α - 5) (α - 2) = 0$
$\Rightarrow α = 5, 2$
$∴ α^{3} = x$
$\Rightarrow x = 125$ and $8$
$cos e c^{- 1} (sec α) + cot^{- 1} (tan α)$