If vm is the speed of sound in moist air and vd is the speed of sound in dry air under identical conditions of pressure and temperature, then

Question

If vm is the speed of sound in moist air and vd is the speed of sound in dry air under identical conditions of pressure and temperature, then (A) vm > vd (B) vm < vd (C) vm = vd (D) vm . vd = 1

Tardigrade Admin · Accepted Answer

sound is nothing but vibration of air so in the presence of water in the air(moist air) the water droplet comes in contact with the vibration and amplify it because velocity of sound is higher in water than in air so amplified sound is created in moist air with higher velocity and obviously in the absence of water droplet or in dry air no amplification is possible and speed remains as it should be in air

Q. If $v_{m}$ is the speed of sound in moist air and $v_{d}$ is the speed of sound in dry air under identical conditions of pressure and temperature, then

$v_{m} > v_{d}$

$v_{m} < v_{d}$

$v_{m} = v_{d}$

$v_{m} . v_{d} = 1$

Q. If vm​ is the speed of sound in moist air and vd​ is the speed of sound in dry air under identical conditions of pressure and temperature, then

vm​>vd​

vm​<vd​

vm​=vd​

vm​.vd​=1

Q. If $v_{m}$ is the speed of sound in moist air and $v_{d}$ is the speed of sound in dry air under identical conditions of pressure and temperature, then

$v_{m} > v_{d}$

$v_{m} < v_{d}$

$v_{m} = v_{d}$

$v_{m} . v_{d} = 1$