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Tardigrade
Question
Mathematics
If θ lies in the first quadrant and 5 tan θ=4, then (5 sin θ-3 cos θ/ sin θ+2 cos θ) is equal to
Q. If
θ
lies in the first quadrant and
5
tan
θ
=
4
, then
s
i
n
θ
+
2
c
o
s
θ
5
s
i
n
θ
−
3
c
o
s
θ
is equal to
198
162
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A
14
5
B
14
3
C
14
1
D
0
Solution:
Given,
tan
θ
=
5
4
∴
sin
θ
=
41
4
and
cos
θ
=
41
5
Now,
s
i
n
θ
+
2
c
o
s
θ
5
s
i
n
θ
−
3
c
o
s
θ
=
41
4
+
2
×
41
5
5
×
41
4
−
3
×
41
5
=
14
5