If the work function for a certain metal is 3.2 × 10-19 J and it is illuminated with light of frequency v=8 × 1014 Hz, the maximum kinetic energy of the photoelectron would be

Question

If the work function for a certain metal is 3.2 × 10-19 J and it is illuminated with light of frequency v=8 × 1014 Hz, the maximum kinetic energy of the photoelectron would be (A) 2.1 × 10-19 J (B) 3.2 × 10-19 J (C) 5.3 × 10-19 J (D) 8.5 × 10-19 J

Tardigrade Admin · Accepted Answer

Maximum KE =h v-φ0 =6.63 × 10-34 × 8 × 1014-3.2 × 10-19 =2.1 × 10-19 J

Q. If the work function for a certain metal is $3.2 \times 1 0^{- 19} J$ and it is illuminated with light of frequency $v = 8 \times 1 0^{14} Hz$ , the maximum kinetic energy of the photoelectron would be

$2.1 \times 1 0^{- 19} J$

$3.2 \times 1 0^{- 19} J$

$5.3 \times 1 0^{- 19} J$

$8.5 \times 1 0^{- 19} J$

Maximum $K E = h v - ϕ_{0}$
$= 6.63 \times 1 0^{- 34} \times 8 \times 1 0^{14} - 3.2 \times 1 0^{- 19}$
$= 2.1 \times 1 0^{- 19} J$

Q. If the work function for a certain metal is 3.2×10−19J and it is illuminated with light of frequency v=8×1014Hz, the maximum kinetic energy of the photoelectron would be

2.1×10−19J

3.2×10−19J

5.3×10−19J

8.5×10−19J