If the vertices of a triangle are A(3,-3), B(-3,3) and C(-3 √3,-3 √3), then the distance between the ortho-centre and the circum-centre is

Question

If the vertices of a triangle are A(3,-3), B(-3,3) and C(-3 √3,-3 √3), then the distance between the ortho-centre and the circum-centre is (A) 6 √2 units (B) 6 √3 units (C) 0 unit (D) None of these

Tardigrade Admin · Accepted Answer

(i) A B C forms an equilateral triangle. (ii) In an equilateral triangle all the geometric centres except ex-centre coincide.

Q. If the vertices of a triangle are $A (3, - 3), B (- 3, 3)$ and $C (- 33, - 33)$ , then the distance between the ortho-centre and the circum-centre is

$62$ units

$63$ units

0 unit

None of these

(i) $A BC$ forms an equilateral triangle.
(ii) In an equilateral triangle all the geometric centres except ex-centre coincide.

Q. If the vertices of a triangle are A(3,−3),B(−3,3) and C(−33​,−33​), then the distance between the ortho-centre and the circum-centre is

62​ units

63​ units