If the velocity of an electron in Bohr’s first orbit is 2.19 × 106 m s-1, what will be the de Broglie wavelength associated with it?

Question

If the velocity of an electron in Bohr’s first orbit is 2.19 × 106 m s-1, what will be the de Broglie wavelength associated with it? (A) 2.19 × 10-6 m (B) 4.38 × 10-6 m (C) 3.32 × 10-10 m (D) 3.32 × 1010 m

Tardigrade Admin · Accepted Answer

λ=(h/mv) =(6.626 × 10-34 J s/9.11 × 10-31 kg × 2.19 × 106 m s-1) =3.32×10-10 m

Q. If the velocity of an electron in Bohr’s first orbit is $2.19 \times 1 0^{6} m s^{- 1}$ , what will be the de Broglie wavelength associated with it?

$2.19 \times 1 0^{- 6} m$

$4.38 \times 1 0^{- 6} m$

$3.32 \times 1 0^{- 10} m$

$3.32 \times 1 0^{10} m$

$λ = \frac{h}{m v}$
$= \frac{6.626 \times 1 0 ^{- 34} J s}{9.11 \times 1 0 ^{- 31} k g \times 2.19 \times 1 0 ^{6} m s ^{- 1}}$
$= 3.32 \times 1 0^{- 10} m$

Q. If the velocity of an electron in Bohr’s first orbit is 2.19×106ms−1, what will be the de Broglie wavelength associated with it?

2.19×10−6m

4.38×10−6m

3.32×10−10m

3.32×1010m