If the variance of 1,2,2,3 is λ , then the value of log2λ is

Question

If the variance of 1,2,2,3 is λ , then the value of log2λ is (A) 8 (B) 1 (C) -1 (D) -2

Tardigrade Admin · Accepted Answer

We have n=4,x1=1,x2=2,x3=2,x4=3 Variance =( displaystyle ∑ xi2/n)-(( displaystyle ∑ xi/n))2 9 displaystyle ∑ xi=8 displaystyle ∑ xi2=18 Variance =(18/4)-((8/4))2 =(9/2)-4=(1/2)

Q. If the variance of $1, 2, 2, 3$ is $λ,$ then the value of $l o g_{2} λ$ is

$8$

$1$

$- 1$

$- 2$

We have $n = 4, x_{1} = 1, x_{2} = 2, x_{3} = 2, x_{4} = 3$ Variance $= \frac{\sum x _{i}^{2}}{n} - (\frac{\sum x _{i}}{n})^{2}$

$9$

$\sum x_{i} = 8 \sum x_{i}^{2} = 18$
Variance $= \frac{18}{4} - (\frac{8}{4})^{2}$
$= \frac{9}{2} - 4 = \frac{1}{2}$

Q. If the variance of 1,2,2,3 is λ, then the value of log2​λ is

8

1

−1

−2

We have n=4,x1​=1,x2​=2,x3​=2,x4​=3 Variance =n∑xi2​​−(n∑xi​​)2 9 ∑xi​=8∑xi2​=18 Variance =418​−(48​)2 =29​−4=21​

Q. If the variance of $1, 2, 2, 3$ is $λ,$ then the value of $l o g_{2} λ$ is

$8$

$1$

$- 1$

$- 2$

We have $n = 4, x_{1} = 1, x_{2} = 2, x_{3} = 2, x_{4} = 3$ Variance $= \frac{\sum x _{i}^{2}}{n} - (\frac{\sum x _{i}}{n})^{2}$

$9$

$\sum x_{i} = 8 \sum x_{i}^{2} = 18$
Variance $= \frac{18}{4} - (\frac{8}{4})^{2}$
$= \frac{9}{2} - 4 = \frac{1}{2}$