Tardigrade
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Tardigrade
Question
Mathematics
If the value of the integral ∫ limits12 e x 2 dx is α, then the value of ∫ limitsee4 √λ n n x dx is :
Q. If the value of the integral
1
∫
2
e
x
2
d
x
is
α
, then the value of
e
∫
e
4
λnn
x
d
x
is :
89
84
Integrals
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A
e
4
−
e
−
α
B
2
e
4
−
e
−
α
C
2
(
e
4
−
e
)
−
α
D
2
e
4
−
1
−
α
Solution:
Put
ln
x
=
t
2
⇒
x
=
e
t
2
⇒
d
x
=
2
t
t
2
d
t
.
Hence
I
=
1
∫
2
t
.2
t
t
2
d
t
.
Now I.B.P. taking
t
as the first function and
2
t
e
t
2
as the second function.