If the symbols V and E represents the gravitational potential and gravitational fieldat a point. It is possible to have

Question

If the symbols V and E represents the gravitational potential and gravitational fieldat a point. It is possible to have (A) V = 0 and E = 0 (B)  V≠ 0 and E≠ 0  (C) V= 0 and E≠ 0  (D)  V≠ 0 and E =0

Tardigrade Admin · Accepted Answer

As, E.d=Δ V=V ⇒ Ed cos θ =Δ V=V For Δ V=V=0 may be E = 0 but θ ≠ 0 or may cos θ =0 but E≠ 0 Thus, the gravitational potential can be zero, while E≠ 0

Q. If the symbols V and E represents the gravitational potential and gravitational fieldat a point. It is possible to have

V = 0 and E = 0

$V \neq = 0$ and $E \neq = 0$

V= 0 and $E \neq = 0$

$V \neq = 0$ and E =0

As, $E . d = Δ V = V$ $\Rightarrow$ $E d cos θ = Δ V = V$ For $Δ V = V = 0$ may be E = 0 but $θ \neq = 0$ or may $cos θ = 0$ but $E \neq = 0$ Thus, the gravitational potential can be zero, while $E \neq = 0$

Q. If the symbols V and E represents the gravitational potential and gravitational fieldat a point. It is possible to have

V = 0 and E = 0

V=0 and E=0

V= 0 and E=0

V=0 and E =0

As, E.d=ΔV=V ⇒ Edcosθ=ΔV=V For ΔV=V=0 may be E = 0 but θ=0 or may cosθ=0 but E=0 Thus, the gravitational potential can be zero, while E=0

$V \neq = 0$ and $E \neq = 0$

V= 0 and $E \neq = 0$

$V \neq = 0$ and E =0

As, $E . d = Δ V = V$ $\Rightarrow$ $E d cos θ = Δ V = V$ For $Δ V = V = 0$ may be E = 0 but $θ \neq = 0$ or may $cos θ = 0$ but $E \neq = 0$ Thus, the gravitational potential can be zero, while $E \neq = 0$