If the surface tension of liquid is 5× 10-2N/m and weight of liquid column is 6.28× 10-4N, then radius of capillary is

Question

If the surface tension of liquid is 5× 10-2N/m and weight of liquid column is 6.28× 10-4N, then radius of capillary is (A)  2× 10-3m  (B)  2.5× 10-3m  (C)  2× 10-4  (D)  4× 10-3m

Tardigrade Admin · Accepted Answer

F=2π rT ⇒ r=(F/2π T) =(6.28× 10-4/2× 3.14× 5× 10-2)=2× 10-3m

Q. If the surface tension of liquid is $5 \times 10^{- 2} N / m$ and weight of liquid column is $6.28 \times 10^{- 4} N,$ then radius of capillary is

$2 \times 10^{- 3} m$

$2.5 \times 10^{- 3} m$

$2 \times 10^{- 4}$

$4 \times 10^{- 3} m$

$F = 2 π r T$
$\Rightarrow$ $r = \frac{F}{2 π T}$ $= \frac{6.28 \times 10 ^{- 4}}{2 \times 3.14 \times 5 \times 10 ^{- 2}} = 2 \times 10^{- 3} m$

Q. If the surface tension of liquid is 5×10−2N/m and weight of liquid column is 6.28×10−4N, then radius of capillary is

2×10−3m

2.5×10−3m

2×10−4

4×10−3m