If the sum of the slopes of the lines given by 4 x2+2 λ x y-7 y2=0 is equal to the product of the slopes, then λ is equal to

Question

If the sum of the slopes of the lines given by 4 x2+2 λ x y-7 y2=0 is equal to the product of the slopes, then λ is equal to (A) -4 (B) 4 (C) -2 (D) 2

Tardigrade Admin · Accepted Answer

4 x2+2 λ x y-7 y2=0 a=4,2 h=2 λ, b=-7 Given, sum of slopers = product of slopers m1+m2=m1 m2 (-2 h/b)=(a/b) (-2 λ/-7)=(4/-7) λ=-2

Q. If the sum of the slopes of the lines given by $4 x^{2} + 2 λ x y - 7 y^{2} = 0$ is equal to the product of the slopes, then $λ$ is equal to

-4

4

-2

2

$4 x^{2} + 2 λ x y - 7 y^{2} = 0$
$a = 4, 2 h = 2 λ, b = - 7$
Given, sum of slopers = product of slopers
$m_{1} + m_{2} = m_{1} m_{2}$
$\frac{- 2 h}{b} = \frac{a}{b}$
$\frac{- 2 λ}{- 7} = \frac{4}{- 7}$
$λ = - 2$

Q. If the sum of the slopes of the lines given by 4x2+2λxy−7y2=0 is equal to the product of the slopes, then λ is equal to

-4

4

-2

2

4x2+2λxy−7y2=0 a=4,2h=2λ,b=−7 Given, sum of slopers = product of slopers m1​+m2​=m1​m2​ b−2h​=ba​ −7−2λ​=−74​ λ=−2

Q. If the sum of the slopes of the lines given by $4 x^{2} + 2 λ x y - 7 y^{2} = 0$ is equal to the product of the slopes, then $λ$ is equal to

$4 x^{2} + 2 λ x y - 7 y^{2} = 0$
$a = 4, 2 h = 2 λ, b = - 7$
Given, sum of slopers = product of slopers
$m_{1} + m_{2} = m_{1} m_{2}$
$\frac{- 2 h}{b} = \frac{a}{b}$
$\frac{- 2 λ}{- 7} = \frac{4}{- 7}$
$λ = - 2$