Question

If the reaction achieves equilibrium at $298K\&$ one bar pressure i.e., standard conditions then equilibrium constant is:

• A. 1
• B. 10
• C. Zero
• D. 6

Answer 1

Answer: (A)

At eqm. $\Delta G=0$

Since standard conditions prevail at eqm,

then $\Delta G={\Delta }^{\circ }G=0$

Now, ${\Delta }^{\circ }G=-2.303RT\log K$

$0=-2.303RT\log K$

$\log K=0$

$K=1$