If the rate of change in velocity w.r.t time is constant and its position after 6th second will be same as that after 11th second then the particle returns to the starting point at time t equals to

Question

If the rate of change in velocity w.r.t time is constant and its position after 6th second will be same as that after 11th second then the particle returns to the starting point at time t equals to (A) 13 s (B) 15 s (C) 17 s (D) 19 s

Tardigrade Admin · Accepted Answer

T = t1 +t2 = 17 s <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b0d2fd1a247c2adcd1868eb1dc6c4096-.png" /> Here acceleration is constant and body returns, therefore initial velocity and acceleration must be in opposite direction as shown above. Therefore particle returns after 17 seconds.

Q. If the rate of change in velocity w.r.t time is constant and its position after $6^{t h}$ second will be same as that after $1 1^{t h}$ second then the particle returns to the starting point at time t equals to

$13 s$

$15 s$

$17 s$

$19 s$

$T = t_{1} + t_{2}$
$= 17 s$

Here acceleration is constant and body returns, therefore initial velocity and acceleration must be in opposite direction as shown above. Therefore particle returns after $17$ seconds.

Q. If the rate of change in velocity w.r.t time is constant and its position after 6th second will be same as that after 11th second then the particle returns to the starting point at time t equals to

13s

15s

17s

19s