Question

If the radius of the dees of cyclotron is $r$, then the kinetic energy of a proton of mass $m$ accelerated by the cyclotron at an oscillating frequency $v$ is

• A. $4{\pi }^2{m}^2{v}^2{r}^2$
• B. $4{\pi }^{2}m{v}^2{r}^2$
• C. $2{\pi }^{2}m{v}^2{r}^2$
• D. ${\pi }^{2}m{v}^2{r}^2$
• E. ${\pi }^2{m}^2{v}^2{r}^2$

Answer 1

Answer: (C)

Given,
$r=$ the outside radius of the dees
$V=$ the speed of the particle when travelling in a path of this radius
$m=$ the mass of proton
Kinetic energy of particles accelerated in a cyclotron
$K=2{\pi }^{2}m{v}^2{r}^2$