Q.
If the quadratic equations 3x2+ax+1=0 and 2x2+bx+1=0 have a common root, then the value of the expression 5ab−2a2−3b2 is
76
97
Complex Numbers and Quadratic Equations
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Solution:
6x2+2ax+2=0 and 6x2+3bx+3=0
subtracting x(2a−3b)−1=0⇒x=2a−3b1 (put in any equation) ∴2(2a−3b)21+2a−3bb+1=0 2+b(2a−3b)+(2a−3b)2=0 4a2+5b2−12ab+2ab−3b2+2=0 −10ab+6b2+4a2+1=0 ⇒5ab−3b2−2a2=1⇒B