If the potential of a capacitor having capacity 6 μ F is increased from 10 volt to 20 volt then increase in its energy is

Question

If the potential of a capacitor having capacity 6 μ F is increased from 10 volt to 20 volt then increase in its energy is (A)  12× 10-6J  (B)  9× 10-4J  (C)  4.5× 10-6J  (D)  2.25× 10-6J

Tardigrade Admin · Accepted Answer

Given: C=6 μ F, V1=10 volt, V2=20 volt Increase in energy E =(1/2) C V222-(1/2) C V12 =(1/2) C(V22-V12) =(1/2) × 6 × 10-6(202-102) =3 × 10-6(202-102) =3 × 10-6 × 300 =9 × 10-4 J

Q. If the potential of a capacitor having capacity $6 μ F$ is increased from $10$ volt to $20$ volt then increase in its energy is

$12 \times 1 0^{- 6} J$

$9 \times 1 0^{- 4} J$

$4.5 \times 1 0^{- 6} J$

$2.25 \times 1 0^{- 6} J$

Q. If the potential of a capacitor having capacity 6μF is increased from 10 volt to 20 volt then increase in its energy is

12×10−6J

9×10−4J

4.5×10−6J

2.25×10−6J

Given : C=6μF,V1​=10 volt, V2​=20 volt Increase in energy E=21​CV222​−21​CV12​ =21​C(V22​−V12​) =21​×6×10−6(202−102) =3×10−6(202−102) =3×10−6×300=9×10−4J

Q. If the potential of a capacitor having capacity $6 μ F$ is increased from $10$ volt to $20$ volt then increase in its energy is

$12 \times 1 0^{- 6} J$

$9 \times 1 0^{- 4} J$

$4.5 \times 1 0^{- 6} J$

$2.25 \times 1 0^{- 6} J$