If the points (3, - 2), (x, 2), (8,8) are collinear, then find the value of x.

Question

If the points (3, - 2), (x, 2), (8,8) are collinear, then find the value of x. (A) 2 (B) 3 (C) 4 (D) 5

Tardigrade Admin · Accepted Answer

Since, the given points are collinear. ∴ (1/2) | beginmatrix3&-2&1 x&2&1 8&8&1 endmatrix|=0 ⇒ 3(2-8)+2(x-8)+1(8x-16)=0 ⇒ -18+2x-16+8x-16=0 ⇒ 10x=50 ⇒ x=5

Q. If the points $(3, - 2), (x, 2), (8, 8)$ are collinear, then find the value of x.

$2$

$3$

$4$

$5$

Since, the given points are collinear.
$∴ \frac{1}{2} ∣ ∣ 3 x 8 - 2 28 111 ∣ ∣ = 0$
$\Rightarrow 3 (2 - 8) + 2 (x - 8) + 1 (8 x - 16) = 0$
$\Rightarrow - 18 + 2 x - 16 + 8 x - 16 = 0$
$\Rightarrow 10 x = 50 \Rightarrow x = 5$

Q. If the points (3,−2),(x,2),(8,8) are collinear, then find the value of x.

2

3

4

5

Since, the given points are collinear. ∴21​∣∣​3x8​−228​111​∣∣​=0 ⇒3(2−8)+2(x−8)+1(8x−16)=0 ⇒−18+2x−16+8x−16=0 ⇒10x=50⇒x=5

Q. If the points $(3, - 2), (x, 2), (8, 8)$ are collinear, then find the value of x.

$2$

$3$

$4$

$5$

Since, the given points are collinear.
$∴ \frac{1}{2} ∣ ∣ 3 x 8 - 2 28 111 ∣ ∣ = 0$
$\Rightarrow 3 (2 - 8) + 2 (x - 8) + 1 (8 x - 16) = 0$
$\Rightarrow - 18 + 2 x - 16 + 8 x - 16 = 0$
$\Rightarrow 10 x = 50 \Rightarrow x = 5$