Question

If the percentage error in length is 0.1% and in time is 0.4% then % error in g will be

• A. 0.35%
• B. 1%
• C. 0.9 %
• D. 0.1%

Answer 1

Answer: (C)

$T=2\pi \sqrt{\frac{l}{g}}org=\frac{4{\pi }^{2}l}{T^2}$
Then, % error in g
$=\left(\frac{\Delta l}{l}\times 100\right)+2\left(\frac{\Delta T}{T}\times 100\right)$
$=0.1\%+2(0.4)\%=0.9\%$