If the LCM and HCF of two polynomials are 90 m5 a6 b3 x2 and m3 a5, respectively, and also one of the monomial is 18 m5 a6 x2, then the other monomial is:

Question

If the LCM and HCF of two polynomials are 90 m5 a6 b3 x2 and m3 a5, respectively, and also one of the monomial is 18 m5 a6 x2, then the other monomial is: (A) 5 m3 a5 b3 (B) 15 m5 a3 b2 (C) 5 m5 a3 b5 (D) 15 m3 a5 b4

Tardigrade Admin · Accepted Answer

Use the formula, HCF × LCM = product of polynomials.

Q. If the LCM and $H CF$ of two polynomials are $90 m^{5} a^{6} b^{3} x^{2}$ and $m^{3} a^{5}$ , respectively, and also one of the monomial is $18 m^{5} a^{6} x^{2}$ , then the other monomial is:

$5 m^{3} a^{5} b^{3}$

$15 m^{5} a^{3} b^{2}$

$5 m^{5} a^{3} b^{5}$

$15 m^{3} a^{5} b^{4}$

Use the formula, $H CF \times L CM =$ product of polynomials.

Q. If the LCM and HCF of two polynomials are 90m5a6b3x2 and m3a5, respectively, and also one of the monomial is 18m5a6x2, then the other monomial is:

5m3a5b3

15m5a3b2

5m5a3b5

15m3a5b4