We have f(x)=16−(x−4)2−1−(x−7)2 Now consider y=16−(x−4)2 ⇒(x−4)2+y2=16,y>0
is a semi circle with cenre (4,0) and radius =4. Hy y=1−(x−7)2 ⇒(x−7)2+y2=1,y>0
is a semi circle with centre (7,0) and radius =1
Now on combining the 2 figures, we have f(x)max= maximum vertical distance between the 2 curves which occurs when x=6.