If the force acting on a body is inversely proportional to its speed, then its kinetic energy is

Question

If the force acting on a body is inversely proportional to its speed, then its kinetic energy is (A) linearly related to time (B) inversely proportional to time (C) inversely proportional to the square of time (D) a constant

Tardigrade Admin · Accepted Answer

Given, force (F) propto (1/v) or ma=(k/v) or m× (v/t)=(k/v) or mv2=kt or (1/2)mv2=k't ⇒ KE propto t

Q. If the force acting on a body is inversely proportional to its speed, then its kinetic energy is

linearly related to time

inversely proportional to time

inversely proportional to the square of time

a constant

Given, force $(F) \propto \frac{1}{v}$
or $ma = \frac{k}{v}$
or $m \times \frac{v}{t} = \frac{k}{v}$
or $m v^{2} = k t$
or $\frac{1}{2} m v^{2} = k^{'} t$
$\Rightarrow$ $K E \propto t$

Q. If the force acting on a body is inversely proportional to its speed, then its kinetic energy is

linearly related to time

inversely proportional to time

inversely proportional to the square of time

a constant

Given, force (F)∝v1​ or ma=vk​ or m×tv​=vk​ or mv2=kt or 21​mv2=k′t ⇒ KE∝t

Given, force $(F) \propto \frac{1}{v}$
or $ma = \frac{k}{v}$
or $m \times \frac{v}{t} = \frac{k}{v}$
or $m v^{2} = k t$
or $\frac{1}{2} m v^{2} = k^{'} t$
$\Rightarrow$ $K E \propto t$