Q.
If the first and the (2n−1)th term of an AP,GP and HP are equal and their nth terms are a,b and c respectively, then
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IIT JEEIIT JEE 1988Sequences and Series
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Solution:
Since, first and (2n−1)th terms are equal.
Let first term be x and (2n−1)th term be y,
whose middle term is tn.
Thus, in arithmetic progression, tn=2x+y=a
In geometric progression, tn=xy=b
In harmonic progression, tn=x+y2xy=c ⇒b2=ac and a>b>c [using AM > GM > HM]
Here, equality holds (i.e. a=b=c) only if all terms are
same. Hence, options (a), (b) and (d) are correct