Question

If the distance between successive compressions and rarefactions is $1m$ and velocity of sound is $360m{s}^{-i}$, then the frequency is

• A. 180 Hz
• B. 45 Hz
• C. 120 Hz
• D. 90 Hz

Answer 1

Answer: (A)

Distance between successive compressions and rarefactions is $\lambda /2$.
$\therefore \frac{\lambda }{2}=1$ or $\lambda =2m$
As $v=v\lambda$
$\therefore v=\frac{v}{\lambda }=\frac{360m{s}^{-1}}{2m}=180Hz$