If the de-Broglie wavelength of a proton is 10-13m, the electric potential through which it must have been accelerated is:

Question

If the de-Broglie wavelength of a proton is 10-13m, the electric potential through which it must have been accelerated is: (A)  4.07× 104 V  (B)  8.2× 104 V  (C)  8.2× 103 V  (D)  4.07× 105 V

Tardigrade Admin · Accepted Answer

λ=(h/√2 m q V) . (10-13)2=((6.6 × 10-34)2/2 × 1.67 × 10-27 × 1.6 × 10-19 V) V=8.2 × 104 Volt .

Q. If the de-Broglie wavelength of a proton is $10^{- 13} m,$ the electric potential through which it must have been accelerated is:

$4.07 \times 10^{4} V$

$8.2 \times 10^{4} V$

$8.2 \times 10^{3} V$

$4.07 \times 10^{5} V$

$λ = \frac{h}{2 m q V} .$
$(1 0^{- 13})^{2} = \frac{( 6.6 \times 1 0 ^{- 34} ) ^{2}}{2 \times 1.67 \times 1 0 ^{- 27} \times 1.6 \times 1 0 ^{- 19} V}$
$V = 8.2 \times 1 0^{4} V o lt .$

Q. If the de-Broglie wavelength of a proton is 10−13m, the electric potential through which it must have been accelerated is:

4.07×104V

8.2×104V

8.2×103V

4.07×105V