If the current in the toroidal solenoid increases uniformly from zero to 6.0 A in 3.0μs. Self inductance of the toroidal solenoid is 40μH. The magnitude of self induced emf is

Question

If the current in the toroidal solenoid increases uniformly from zero to 6.0 A in 3.0μs. Self inductance of the toroidal solenoid is 40μH. The magnitude of self induced emf is (A) 24V (B) 48V (C) 80V (D) 160V

Tardigrade Admin · Accepted Answer

Current in toroidal solenoid increases uniformly from 0 to

6.0 A

in

3.0 μ s

.
Magnitude of self induced emf is given by

∣ ε ∣ = L ∣ ∣ \frac{d i}{d t} ∣ ∣

[Symbols have usual meanings]

= (40 \times 1 0^{- 6}) (\frac{6 - 0}{3.0 \times 1 0 ^{- 6}}) = 80 V

Q. If the current in the toroidal solenoid increases uniformly from zero to $6.0 A$ in $3.0 μ s .$ Self inductance of the toroidal solenoid is $40 μ H$ . The magnitude of self induced emf is

$24 V$

$48 V$

$80 V$

$160 V$

Current in toroidal solenoid increases uniformly from 0 to $6.0 A$ in $3.0 μ s$ .
Magnitude of self induced emf is given by
$∣ ε ∣ = L ∣ ∣ \frac{d i}{d t} ∣ ∣$
[Symbols have usual meanings]
$= (40 \times 1 0^{- 6}) (\frac{6 - 0}{3.0 \times 1 0 ^{- 6}}) = 80 V$

Q. If the current in the toroidal solenoid increases uniformly from zero to 6.0A in 3.0μs. Self inductance of the toroidal solenoid is 40μH. The magnitude of self induced emf is

24V

48V

80V

160V