Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If the constant term, in binomial expansion of (2 xr+(1/x2))10 is 180 , then r is equal to
Q. If the constant term, in binomial expansion of
(
2
x
r
+
x
2
1
)
10
is
180
, then
r
is equal to ______
561
145
JEE Main
JEE Main 2021
Binomial Theorem
Report Error
Answer:
8
Solution:
(
2
x
r
+
x
2
1
)
10
General term
=
10
C
R
(
2
x
2
)
10
−
R
x
−
2
R
⇒
2
10
−
R
10
C
R
=
180
……
.
(
1
)
&
(
10
−
R
)
r
−
2
R
=
0
r
=
10
−
R
2
R
r
=
10
−
R
2
(
R
−
10
)
+
10
−
R
20
⇒
r
=
−
2
+
10
−
R
20
……
..
(
2
)
R
=
8
or
5
reject equation (1) not satisfied
At
R
=
8
2
10
−
R
10
C
R
=
180
⇒
r
=
8