If the coefficient of friction between A and B is μ, the maximum horizontal acceleration of the wedge A for which B will remain at rest w.r.t the wedge is :

Question

If the coefficient of friction between A and B is μ, the maximum horizontal acceleration of the wedge A for which B will remain at rest w.r.t the wedge is : (A) μ g (B) g((1+μ/1-μ)) (C) ( g /μ) (D) g ((1-μ/1+μ))

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/74c7334043035ea35e85af873a966edc-.png" /> N=m g cos 45°+m a sin 45° N=(m g+m a/√2) ma cos 45°=m g sin 45°+μ N ...(2) Put the value of N (m a/√2)=(m g/√2)+(μ(m g+m a)/√2) a=g((1+μ/1-μ))

Q. If the coefficient of friction between $A$ and $B$ is $μ$ , the maximum horizontal acceleration of the wedge $A$ for which $B$ will remain at rest w.r.t the wedge is :

$μ g$

$g (\frac{1 + μ}{1 - μ})$

$\frac{g}{μ}$

$g (\frac{1 - μ}{1 + μ})$

$N = m g cos 4 5^{\circ} + ma sin 4 5^{\circ}$
$N = \frac{m g + ma}{2}$
$ma cos 4 5^{\circ} = m g sin 4 5^{\circ} + μ N ... (2)$
Put the value of $N$
$\frac{ma}{2} = \frac{m g}{2} + \frac{μ ( m g + ma )}{2}$
$a = g (\frac{1 + μ}{1 - μ})$

Q. If the coefficient of friction between A and B is μ, the maximum horizontal acceleration of the wedge A for which B will remain at rest w.r.t the wedge is :

μg

g(1−μ1+μ​)

μg​

g(1+μ1−μ​)