We know that, the acute angle θ between two lines with slopes m1 and m2 is given by tanθ=∣∣1+m1m2m2−m1∣∣.......(i)
Let m1=21,m2=m and θ=4π
Now, putting these values in Eq. (i), we get tan4π=∣∣1+21mm−21∣∣ 1=∣∣1+21mm−21∣∣
which gives 1+21mm−21=1
or 1+21mm−21=−1
Therefore, m=3 or m=−31
Hence, slope of the other line is 3 or −31.