Question

If solubility product of $HgS{O}_4$ is $6.4\times {10}^{-5}$ , then its solubility is

• A. $8\times {10}^{-3}mol/L$
• B. $6.4\times {10}^{-5}mol/L$
• C. $6.4\times {10}^{-3}mol/L$
• D. $2.8\times {10}^{-6}mol/L$

Answer 1

Answer: (A)

Key Idea: First find the relationship between solubility and solubility product of $HgS{O}_4$ then substitute the values and calculate to find the value of solubility of $HgS{O}_4$ . Let the solubility of $HgS{O}_4$ be s mol/L $HgS{O}_{4}H{g}^{2+}+S{O}_4^{2-}$ $K_{sp}=[H{g}^{2+]}[S{O}_4^{2-}]$ $=S\times S$ $=S^2$ or $S=\sqrt{K_{sp}}$ $=\sqrt{6.4\times {10}^{-5}}$ $=8\times {10}^{-3}mol/L$