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Tardigrade
Question
Mathematics
If sin (x-y)= cos (x+y)=1 / 2, then the values of x and y lying between 0° and 180° are
Q. If
sin
(
x
−
y
)
=
cos
(
x
+
y
)
=
1/2
, then the values of
x
and
y
lying between
0
∘
and
18
0
∘
are
2314
222
Trigonometric Functions
Report Error
A
x
=
4
5
∘
,
y
=
1
5
∘
B
x
=
4
5
∘
,
y
=
13
5
∘
C
x
=
16
5
∘
,
y
=
1
5
∘
D
x
=
16
5
∘
,
y
=
13
5
∘
Solution:
sin
(
x
−
y
)
=
1/2
⇒
x
−
y
=
π
/6
or
6
5
π
cos
(
x
+
y
)
=
1/2
⇒
x
+
y
=
3
π
,
6
5
π
∴
After solving we get
x
=
4
5
∘
,
y
=
1
5
∘