Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If S=1(25)+2(24)+3(23)+......+24(2)+25(1) , then the value of (S/900) is equal to
Q. If
S
=
1
(
25
)
+
2
(
24
)
+
3
(
23
)
+
......
+
24
(
2
)
+
25
(
1
)
, then the value of
900
S
is equal to
1978
227
NTA Abhyas
NTA Abhyas 2020
Sequences and Series
Report Error
Answer:
3.25
Solution:
S
=
∑
r
=
1
25
r
(
26
−
r
)
=
26
∑
r
=
1
25
r
−
∑
r
=
1
25
r
2
=
26
×
2
25
×
26
−
6
25
×
26
×
51
=
2
25
×
26
(
26
−
3
51
)
=
4
25
×
2613
×
9
⇒
900
S
=
4
13
=
3.25