If potassium chlorate is 80 % pure then 48 g of oxygen would be produced from:

Question

If potassium chlorate is 80 % pure then 48 g of oxygen would be produced from: (A) 153.12 g of KClO 3 (B) 120 g of KClO 3 (C) 20 g of KClO 3 (D) 90 g of KClO 3

Tardigrade Admin · Accepted Answer

underset2 × 122.5 g2 KClO 3 arrow underset3 × 32 g2 KCl +3 O 2 3 × 32 g of O 2 is produced from KClO 3=245 g 48 g of O2, is produced from KClO3=245 g ∴ 80 % KClO 3 needed =(122.5 × 100/80) =153.12 g

Q. If potassium chlorate is $80%$ pure then $48 g$ of oxygen would be produced from:

$153.12 g$ of $K Cl O_{3}$

$120 g$ of $K Cl O_{3}$

$20 g$ of $K Cl O_{3}$

$90 g$ of $K Cl O_{3}$

$2 \times 122.5 g 2 K Cl O_{3} \to 3 \times 32 g 2 K Cl + 3 O_{2}$

$3 \times 32 g$ of $O_{2}$ is produced from $K Cl O_{3} = 245 g$

$48 g$ of $O_{2}$ , is produced from $K Cl O_{3} = 245 g$

$∴ 80% K Cl O_{3}$ needed $= \frac{122.5 \times 100}{80}$

$= 153.12 g$

Q. If potassium chlorate is 80% pure then 48g of oxygen would be produced from:

153.12g of KClO3​

120g of KClO3​

20g of KClO3​

90g of KClO3​