If plates of charged parallel plate capacitor are pulled apart:

Question

If plates of charged parallel plate capacitor are pulled apart: (A) The capacitance increases (B) Charge increases (C) Potential difference remains same (D) Potential difference increases

Tardigrade Admin · Accepted Answer

When separation increases capacitance decreases C propto (1/ d ) and V=(q/C) ∴ V increases

Q. If plates of charged parallel plate capacitor are pulled apart:

The capacitance increases

Charge increases

Potential difference remains same

Potential difference increases

When separation increases capacitance decreases
$C \propto \frac{1}{d}$
and $V = \frac{q}{C}$
$∴$ V increases

Q. If plates of charged parallel plate capacitor are pulled apart:

The capacitance increases

Charge increases

Potential difference remains same

Potential difference increases

When separation increases capacitance decreases C∝d1​ and V=Cq​ ∴ V increases

When separation increases capacitance decreases
$C \propto \frac{1}{d}$
and $V = \frac{q}{C}$
$∴$ V increases