Given, equation of hyperbola x2−y2=a2...(i)
If P(x1,y1) is a point on Eq. (i), then x12−y12=a2...(ii)
Now, SP=ex1−a
and SP′=ex1+a ∴SP⋅SP′=(ex1−a)(ex1+a) =e2⋅x12−a2 =2x12−a2( since, for x2−y2=a2,e=2) =2x12−(x12−y12)[using Eq. (i)] =x12+y12