If p, q and r are three propositions, then which of the following combination of truth values of p, q and r makes the logical expression (p ∨ q) ∧((∼ p) ∨ r) arrow((∼ q) ∨ r) false?

Question

If p, q and r are three propositions, then which of the following combination of truth values of p, q and r makes the logical expression (p ∨ q) ∧((∼ p) ∨ r) arrow((∼ q) ∨ r) false? (A) p=T, q=T, r=F (B) p=T, q=F, r=T (C) p=F, q=T, r=F (D) p=T, q=F, r=F

Tardigrade Admin · Accepted Answer

Correct answer is (c) p=F, q=T, r=F

Q. If $p, q$ and $r$ are three propositions, then which of the following combination of truth values of $p, q$ and $r$ makes the logical expression ${(p \lor q) \land ((\sim p) \lor r)} \to ((\sim q) \lor r)$ false?

$p = T, q = T, r = F$

$p = T, q = F, r = T$

$p = F, q = T, r = F$

$p = T, q = F, r = F$

Correct answer is (c) $p = F, q = T, r = F$

Q. If p,q and r are three propositions, then which of the following combination of truth values of p,q and r makes the logical expression {(p∨q)∧((∼p)∨r)}→((∼q)∨r) false?

p=T,q=T,r=F

p=T,q=F,r=T

p=F,q=T,r=F

p=T,q=F,r=F