Given P={a,b,c} and Q={r} P×Q={(a,r),(b,r),(c,r)} Q×P={(r,a),(r,b),(r,c)}
Since, by the definition of equality of ordered pairs,
the pair (a,r) is not equal to the pair (r,a),
we conclude that P×Q=Q×P
However, the number of elements in each set will be the same.