If overset arrow E=(E0 x/a) hati(.x-mt.) then flux through the shaded area is:-

Question

If overset arrow E=(E0 x/a) hati(.x-mt.) then flux through the shaded area is:- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-maz3dni7slku7o3z.jpg" /> (A) E0a2 (B) Zero (C) E0a3 (D) -E0a3

Tardigrade Admin · Accepted Answer

E=(E0/a)x hati E at shaded region E=E0(a hati/a)⇒ E=E0 hati ⇒ φ=E0a2

Q. If $E \to = \frac{E _{0} x}{a} \hat{i} (x - m t)$ then flux through the shaded area is:-

$E_{0} a^{2}$

Zero

$E_{0} a^{3}$

$- E_{0} a^{3}$

$E = \frac{E _{0}}{a} x \hat{i}$
$E$ at shaded region
$E = E_{0} \frac{a i ^}{a} \Rightarrow E = E_{0} \hat{i}$
$\Rightarrow ϕ = E_{0} a^{2}$

Q. If E→=aE0​x​i^(x−mt) then flux through the shaded area is:-

E0​a2

Zero

E0​a3

−E0​a3

E=aE0​​xi^ E at shaded region E=E0​aai^​⇒E=E0​i^ ⇒ϕ=E0​a2

Q. If $E \to = \frac{E _{0} x}{a} \hat{i} (x - m t)$ then flux through the shaded area is:-

$E_{0} a^{2}$

$E_{0} a^{3}$

$- E_{0} a^{3}$

$E = \frac{E _{0}}{a} x \hat{i}$
$E$ at shaded region
$E = E_{0} \frac{a i ^}{a} \Rightarrow E = E_{0} \hat{i}$
$\Rightarrow ϕ = E_{0} a^{2}$