If one mole electrons is passed through the solutions of Al Cl 3, AgNO 3 and MgSO 4, in what ratio Al , Ag and Mg will be deposited at the electrodes?

Question

If one mole electrons is passed through the solutions of Al Cl 3, AgNO 3 and MgSO 4, in what ratio Al , Ag and Mg will be deposited at the electrodes? (A) 3: 6: 2 (B) 2: 6: 3 (C) 1: 2: 3 (D) 3: 2: 1

Tardigrade Admin · Accepted Answer

e qA l=e qA g=e qM g eq = moles × n - factor A l+3+3 e- arrow A l A g++e- arrow A g M g+2+2 e- arrow M g (1/3) mol Al: 1 mol Ag: (1/2) mol Mg or 2: 6: 3

Q. If one mole electrons is passed through the solutions of $A lC l_{3}, A g N O_{3}$ and $M g S O_{4}$ , in what ratio $A l, A g$ and $M g$ will be deposited at the electrodes?

$3 : 6 : 2$

$2 : 6 : 3$

$1 : 2 : 3$

$3 : 2 : 1$

$e q_{A l} = e q_{A g} = e q_{M g}$
eq $=$ moles $\times n -$ factor
$A l^{+ 3} + 3 e^{-} \to A l$
$A g^{+} + e^{-} \to A g$
$M g^{+ 2} + 2 e^{-} \to M g$
$\frac{1}{3} m o l A l : 1 m o l A g : \frac{1}{2} m o l M g$
or $2 : 6 : 3$

Q. If one mole electrons is passed through the solutions of AlCl3​,AgNO3​ and MgSO4​, in what ratio Al,Ag and Mg will be deposited at the electrodes?

3:6:2

2:6:3

1:2:3

3:2:1