Question

If n = 2 for $H{e}^{+}$ ion than find out the wave length

• A. 3.32 $\mathring{A}$
• B. 6.42 $\mathring{A}$
• C. 1.47 $\mathring{A}$
• D. 2.37 $\mathring{A}$

Answer 1

Answer: (A)

$2\pi r=n\lambda$
$2\pi \times 0.529\times \frac{n^2}{Z}=n\lambda$
$\lambda =\frac{2\pi \times 0.529\times n^2}{n\times Z}$
$\lambda =\frac{2\times 3.14\times 0.529\times 2^2}{2\times 2}$
$\lambda =3.33\mathring{A}$